Hello,
3(2m-9+6m)=3m+29-7m
==>3(8m-9)=-4m+29
==>24m+4m=29+27
==>28m=56
==>m=2
Answer B
Answer:
Sam has the more convincing victory with a greater Zscore value
Step-by-step explanation:
Given that :
Year 1:
Mean finish time (m) = 185.64
Standard deviation (s) = 0.314
Sam's time (x1) = 185.29
Year 2:
Mean finish time (m) = 110.3
Standard deviation (s) = 0.129
Rita's time (x1) = 110.02
Zscore = (x - mean) / standard deviation
Sam's Zscore :
(185.29 - 185.64) / 0.314
= - 0.35 / 0.314
= −1.114649
= - 1.115
Rita's Zscore :
(110.02 - 110.3) / 0.129
= - 0.28 / 0.129
= −2.170542
= - 2.171
Sam has the more convincing victory with a greater Zscore value
Answer:
•A c-chart is the appropriate control chart
• c' = 8.5
• Control limits, CL = 8.5
Lower control limits, LCL = 0
Upper control limits, UCL = 17.25
Step-by-step explanation:
A c chart is a quality control chart used for the number of flaws per unit.
Given:
Past inspection data:
Number of units= 100
Total flaws = 850
We now have:
c' = 850/100
= 8.5
Where CL = c' = 8.5
For control limits, we have:
CL = c'
UCL = c' + 3√c'
LCL = c' - 3√c'
The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively
Calculating the various control limits we have:
CL = c'
CL = 8.5
UCL = 8.5 + 3√8.5
= 17.25
LCL = 8.5 - 3√8.5
= -0.25
A negative LCL tend to be 0. Therefore,
LCL = 0
Answer: she is NOT correct the answer should be X= 19
How?:
the equation was 5x = 95
the 5 and x is being multiplied the opposite of multiplication is dividing
so 95/5= 19
therefor x= 19 and NOT 90