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2 years ago

Find the next 3 terms in this sequence.... 17,25,33

Mathematics

2 answers:

Lelu [443]2 years ago

8 0

41,49,57 are the next terms in the sequence you add 8 each time

Sloan [31]2 years ago

6 0

Each term is adding 8

so 33+8=41
41+8=49
49+8=57

the next 3 terms are 41,49, and 57

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WARNING : NON SENSE ANSWER REPORT TO MODERATOR

Rzqust [24]

Answer:

$\frac{180}{147}$

Step-by-step explanation:

Simplify $(\frac{3}{-7} - \frac{11}{21} )$

$=> \frac{(-3 \times 3) - 11}{21}$

$=> \frac{-9 - 11}{21}$

$=> \frac{-20}{21}$

Find the additive inverse of $\frac{-20}{21}$ by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of $\frac{-20}{21}$ .

$=> x + \frac{-20}{21} = 0$

$=> x = 0 - (-\frac{20}{21}) = \frac{20}{21}$

Simplify $(\frac{9}{5} \div \frac{7}{5} )$

$=> \frac{9}{5} \times \frac{1}{\frac{7}{5} }$

$=> \frac{9}{5} \times \frac{5}{7}$

$=> \frac{9}{7}$

Now, find the product of $\frac{9}{7}$ & $\frac{20}{21}$

$=> \frac{9}{7} \times \frac{20}{21}$

$=> \frac{180}{147}$

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Sati [7]

Answer:

E and F

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