the original price is "x", or 100%.
but we know that if we reduce "x" by 20%, namely 100% - 20% = 80%, the 80% of "x" is really £50, what is "x" or the 100% anyway?
Answer:
A.) (7t³ + 2k^4)(7t³ - 2k^4)
Step-by-step explanation:
Factor the following:
49 t^6 - 4 k^8
49 t^6 - 4 k^8 = (7 t^3)^2 - (2 k^4)^2:
(7 t^3)^2 - (2 k^4)^2
Factor the difference of two squares. (7 t^3)^2 - (2 k^4)^2 = (7 t^3 - 2 k^4) (7 t^3 + 2 k^4):
Answer: (7 t^3 - 2 k^4) (7 t^3 + 2 k^4)
Answer:
Explanation:
First we find what x is:
x + 1/x = 12
x + 1 = 12x
1 = 12x - x
1 = 11x
1/11 = x
Or x = 1/11
Plug x value in x^3 + 1/x^3
(1/11)^3 + 1/(1/11)^3
= (1^3/11^3)+ 1/(1^3/11^3)
= (1/1331 + 1)/1/1331
= (1/1331 + 1331/1331)/1/1331
= 1332/1331 x 1331/1
= 1332/1
= 1332
Therefore, x^3 + 1/x^3 = 1332
Y=.25x +700 ; 200 miles
I think the inequality is right
