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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Answer:
supplementary angles
Step-by-step explanation:
they are on the same line, so they sum up to 180°
Given:
30-hour review course average a score of 620 on that exam.
70-hour review course average a score of 749.
To find:
The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.
Solution:
Let x be the number of hours of review course and y be the average score on that exam.
30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).
70-hour review course average a score of 749. So, the linear function passes through the point (70,749).
The linear function passes through the points (30,620) and (70,749). So, the linear equation is:
Adding 620 on both sides, we get
We need to find the y-value for 
.
Therefore, the required linear equation for the given situation is and the average score for persons taking a 57-hour review course is 707.1.
Answer:
the first one
Step-by-step explanation:
the two lines intersect exactly at 5, -3
4 babies and 7 adults
B head=4x1=4 Aheads (3x7)=21 21+4=25 heads
B wings 4x2=8 A wings(4x7)=28 28+8=36
