I am too lazy to do question 6 if u want the answer tell me
Let the given complex number
z = x + ix =
We have to find the standard form of complex number.
Solution:
∴ x + iy =
Rationalising numerator part of complex number, we get
x + iy =
⇒ x + iy =
Using the algebraic identity:
(a + b)(a - b) = -
⇒ x + iy =
⇒ x + iy = [ ∵ ]
⇒ x + iy =
⇒ x + iy =
⇒ x + iy =
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
Iván used to measure the catsup the same as those given
8 is the answer, yw have a nice day:)
To answer this, we need to see the polynomial. Descending order is in a way that the first term of the polynomial will be three, the second (in descending order, two....and so on).
420t+20t3-210t2
In descending order is:
20t^3 - 210t^2 + 420t
So, the option is number two.