Answer:
1.72m
Explanation:
Step 1:
Data obtained from the question.
Displacement (x) = 0.15 m
Spring constant (K) = 300 N/m
Mass (m) = 0.2 kg
Height (h) =?
Step 2:
Determination of the energy in the spring.
The energy is a spring can be obtained by the following equation:
E = 1/2 kx^2
E = 1/2 x 300 x 0.15^2
E = 150 x 0.0225
E = 3.375J
Step 3:
Determination of the maximum height.
At maximum height, the energy stored is the spring is equal to the potential energy i.e
Energy stored in the string = potential energy
E = P.E
Recall:
Potential energy = mgh
Where:
m is the mass = 0.2kg
g is the acceleration due to gravity = 9.8m/s2
h is the height. =?
Potential energy (P.E) = 3.375J
PE = mgh
3.375 = 0.2 x 9.8 x h
Divide both side by 0.2 x 9.8
h = 3.375/ (0.2 x 9.8)
h = 1.72m
Therefore, the maximum height of the box is 1.72m
H = 11 m, the vertical distance that the bullet falls.
Initial vertical velocity = 0
Horizontal velocity = 144.7 m/s
The time, t, taken to fall 11 m is given by
(1/2)*(9.8 m/s²)*(t s)² = (11 m)
4.9t² = 11
t = 1.4983 s
If aerodynamic resistance is ignored, the horizontal distance traveled before the bullet hits the ground is
d = (144.7 m/s)*(1.4983 s) = 216.8 m
Answer: 216.8 m
Answer: The maximum possible speed v is √2( hν - Ф ) / m
Explanation: You could be referring to the provided explanation, despite the fact that the question isn't comprehensive. When a photon collides with the surface of any metal, it transmits all of its energy to the electron in the atom. The collision causes the electron to travel with a certain amount of kinetic energy. This is referred to as the photoelectric effect. The maximum kinetic energy is calculated using Einstein's equation for the photoelectric effect:
K.E. = hν - Ф
½ mv² = hν - Ф
Hence the maximum possible speed is:
v = √2( hν - Ф ) / m
For more information on the photoelectric effect refer to this link: brainly.com/question/25027428
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Answer:
0.435atm
Explanation:
cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains air with a volume of 0.185 m3 at a pressure of 0.740 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.315 m3. If the temperature remains constant, what is the final value of the pressure?
Given
Initial pressure P1= 0.740atm
Initial volume V1= 0.185 m3
Final pressure P2= ?
Final volume V2= 0.315 m3
At constant temperature, the pressure of a syste is inversely proportional to volume, by Boyles law then
P1V1=P2V2
P2=P1V1/V2
=(0.185*0.740)/0.315
0.1369/0.315
= 0.435atm
Therefore, final pressure is 0.435atm
Speed= (frequency) x (wavelength)
= (2 per second) x (5 cm) = <em><u>10 cm/sec .</u></em>