A=F/m
a=(3000000)/(20000)
a=15 m/s^2
To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,
Here,
k = Coulomb's constant
= Charge at each object
r = Distance between them
As the distance is doubled so,
Therefore the factor is 1/4
Answer: the most potential energy == 5 kg book, 2 m from the ground= 98 Joules
Explanation:
potential energy = m g h
m = mass
g = acceleration due gravity = 9.8 m/s²
h = distance above ground
1. Pe₁ = 1 kg x 2 m x g = 2 g
2. Pe₂ = 5 kg x 2 m x g = 10 g = 10 kg m x 9,8 m/s² = 98 Joules
3. Pe₃ = 1 kg x 0,5 m x g = 0,5 g
4. Pe₄ = 5 kg x 0.5 m x g = 2,5 g
10 > 2,5 > 2 >0,5
1 Kilojoule [kJ] = 737.562 149 277 27 Foot pound force [ftlbf]
Answer:
B 14.5 m/s to the east
Explanation:
We can solve this problem by using the law of conservation of momentum.
In fact, if the system is isolated, the total momentum of the system must be conserved.
Here the total momentum before the stuntman reaches the skateboard is:
where
M = 72.0 kg is the mass of the stuntman
v = 15.0 m/s is his initial velocity (to the east)
The total momentum after the stuntmen reaches the skateboard is:
where
m = 2.50 kg is the mass of the skateboard
v' is the final velocity of the stuntman and the skateboard
Since momentum must be conserved, we have
And solvign for v',
And since the sign is the same as v, the direction is the same (to the east).