After 25 days, it remains radon 5.9x10^5 atoms.
Half-life is the time required for a quantity (in this example number of radioactive radon) to reduce to half its initial value.
N(Ra) = 5.7×10^7; initial number of radon atoms
t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days
n = 25 days / 3.8 days
n = 6.58; number of half-lifes of radon
N1(Ra) = N(Ra) x (1/2)^n
N1(Ra) = 5.7×10^7 x (1/2)^6.58
N1(Ra) = 5.9x10^5; number of radon atoms after 25 days
The half-life is independent of initial concentration (size of the sample).
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Answer:
-74.6 kj/mol
Explanation:
you can see the answer at the pic
Answer:
2.067 x 10⁻⁷ M/min.
Explanation:
- Knowing that the rate of the reaction is the change in the concentration of reactants (decrease) or the products (increase) with time.
- For the reaction: <em>2NOCl ⇄ 2NO + Cl₂,</em>
<em>Rate of the reaction = - 1/2 d[NOCl]/dt = 1/2 d[NO]/dt = d[Cl₂]/dt</em>
∵ d[Cl₂] = 3.39 x 10⁻³ M, dt = 1.64 x 10³ min.
∴ Rate of the reaction = d[Cl₂]/dt = (3.39 x 10⁻³ M) / (1.64 x 10³ min) = 2.067 x 10⁻⁷ M/min.
Answer:
128gCaCl2 per 200gH2O
Explanation:
I might be wrong rlly srry if I am:/ Hope this helps doe have a wonderful day