2 years ago

A Truck with a mass of 1500 kg is decelerated At a rate of 5m/s2. how much force did this require

Physics

1 answer:

Marianna [84]2 years ago

6 0

(1500 kg)*(5 m/s^2) = 7500 N

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Zigmanuir [339]

Radial acceleration is given by

$a_{rad}= \frac{v^2}{r}$
where

$v=r \omega$
then

$a_{rad}= \frac{r^2 \omega^2}{r}=r\omega^2$

Now

$70\omega^2=3.90 \frac{m}{s^2} \\ \\ \omega= \sqrt{ \frac{3.9}{70} }$

Using the relation

$\omega=2 \pi f$

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$\frac{60}{2 \pi}\sqrt{ \frac{3.9}{70}} =2.254rpm$

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2 years ago

Which factor affects the angle of sunlight on Earth? The distance between Earth and the sun Earth's tilt from its axis The path

Rainbow [258]

Earth’s tilt from its axis.
For explanation:
The angle in which Earth is at is 23.5°. This causes its tilt which affects how the Sun’s light hits Earth