Answer:
Explanation:
We shall apply Ampere's circuital law to find out magnetic field . It is given as follows.
∫B.dl = μ₀ I , B is magnetic field , I is current , μ₀ is permeability .
Radius of the wire r = 1.2 x 10⁻³ m
magnetic field B will be circular in shape around the wire. If B is uniform
∫B.dl = B x 2πr
B x 2πr = μ₀ I
B = μ₀ I / 2πr
= 4π x 10⁻⁷ x 37 /2πx1.2 x 10⁻³
= 10⁻⁷ x 2x37 / 1.2 x 10⁻³
= 61.67 x 10⁻⁴ T
= 62 x 10⁻⁴ T
Answer:
The angular acceleration of the wheel is -6.54 rad/s²
Explanation:
We'll use the equations of motion for this.
w = 2πf
f = 75 rpm = 1.25 rps = 1.25 rev/s
w₀ = initial angular velocity = 2π × 1.25 = 7.85 rad/s
w = final angular velocity = 0 rad/s
t = 1.2 s
α = ?
w = w₀ + αt
0 = 7.85 + 1.2α
α = 7.85/1.2 = - 6.54 rad/s²
Answer:0.302
Explanation:
Given
mass of crate m=27 kg
Force required to set crate in motion is 80 N
Once the crate is set in motion 56 N is require to move it with constant velocity
i.e. 80 N is the amount of force needed to just overcome static friction and 56 is the kinetic friction force
thus
where is the coefficient of static friction and N is Normal reaction