The Reactance of a Capacitor is t<u>he resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. </u>This is measured in ohms (Ω) and its formula is:
(1)
Where:
is the Reactance in ohms (Ω)
is the frequency of the alternating current in Hertz (
)
is the Capacitance of the Capacitor in Farad (
)
In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.
Note 
Well, with the given data we have to solve (1):
Then:
XC=0.0159 Ω This is the Reactance of the Capacitor
Answer:
48 - 3X
Step-by-step explanation:
( 52+2) - 3x - 6
54 - 3x - 6 So first we deal with the numbers in brackets and that is 52 + 2 giving us 54.
54 - 6 - 3x Then you simplify the expression that is collecting like terms so then we subtract 6 from 54
48 - 3x This is the final expression after simplifying
HOPE THIS HELPED
9514 1404 393
Answer:
75 in^2
Step-by-step explanation:
The central vertical rectangle (including "ears") has dimensions
3 in wide by (9+2+2) = 13 in tall
Its area is
A = LW = (3 in)(13 in) = 39 in^2
__
The two rectangles either side of that have dimensions 2 in by 9 in. The area of each of them is
A = LW = (2 in)(9 in) = 18 in^2
__
The total net area is the sum of the areas of the parts:
left rectangle + central rectangle + right rectangle
= 18 in^2 + 39 in^2 + 18 in^2 = 75 in^2 . . . . surface area of the net
From V= 4/3*pi*r^3
<span>dV/dt = 4pi(r^2)dr/dt </span>
<span>so when dV/dt=30 and r = 19 </span>
<span>30 = 4pi(361)dr/dt </span>
<span>dr/dt = 30/[4pi(361)] </span>
<span>now in </span>
<span>A = 4pir^2 </span>
<span>dA/dt = 8pi(r)dr/dt </span>
<span>= 8pi(19)*30/[4pi(361)] </span>
<span>= you finish it.</span>
<span>HOPE THIS HELPS.
</span>
Answer:
Step-by-step explanation:
if y is hypotonuse and x is opposite side:
sin 34=x/8
8*sin 34=x
x=4.47 (3 sf)
tell me in comment if i interpreted question wrong ._.
