X = first integer, y = second integer (right after x)
since y is right after x, we can say
y = x+1
If the product of the two integers (x and y) is 42, then
x*y = 42
x*( y ) = 42
x*( x+1 ) = 42 ... y is replaced with x+1
x*x + x*1 = 42
x^2 + x = 42
x^2 + x - 42 = 0
(x + 7)(x - 6) = 0 ... factor
x + 7 = 0 or x - 6 = 0
x = -7 or x = 6
The result must be positive as the problem states it, so we toss out x = -7
The only answer is x = 6
If x = 6, then
y = x+1
y = 6+1
y = 7
The two consecutive numbers are 6 and 7
The final answer is 6
Sure enough, 6*7 = 42 checks out
The given equation with t -1 is:
(t – 1)^3 + 6 (t – 1)^2 + 12 (t – 1) + 8
Expand each term before combining for easier visualization:
(t – 1)^3 = t^3 – 3 t^2 + 3t – 1
6 (t – 1)^2 = 6 t^2 – 12 t + 6
12 (t – 1) = 12 t - 12
Then substitute and combine:
-> t^3 – 3 t^2 + 3t – 1 + 6 t^2 – 12 t + 6 + 12 t – 12 + 8
t^3 + 3 t^2 + 3 t + 1 (ANSWER)
Answer:
Remember, a homogeneous system always is consistent. Then we can reason with the rank of the matrix.
If the system Ax=0 has only the trivial solution that's mean that the echelon form of A hasn't free variables, therefore each column of the matrix has a pivot.
Since each column has a pivot then we can form the reduced echelon form of the A, and leave each pivot as 1 and the others components of the column will be zero. This means that the reduced echelon form of A is the identity matrix and so on A is row equivalent to identity matrix.
Answer:
explanation:
put x values in the function in order to find y values.
<u> ___x___ ___y___ </u>
0 | -5
1 | -4.2
2 | -3.4
3 | -2.6
4 | -1.8
5 | -1
6 | -0.2
You will get both of the fractions over the same denominator, so it will be 27/63 and 56/63, then you will add the two numerators, so it will then come out to 83/63, and you will then simplify that by subtracting 63 from 83, and will get 1 20/63