Answer: if doing it on ck-12 the answer is 40.1
Explanation:
Formal Charge is calculated as, Lewis structure is attached below,
Formal Charge = [# of valence electrons] - [electrons in lone pairs + 1/2 the number of bonding electrons]
# of valence electrons of Cl = 7
electrons in lone pairs = 4
number of bonding electrons = 6
Formal Charge = [7] - [4 + 6/2]
Formal Charge = [7] - [4 + 3]
Formal Charge = [7] - [7]
Formal Charge = 0
Result: Formal charge on Cl in ClF₃ is
zero.
The answers would be 3 and 2 so the subscripts would both equal 6.
Answer:
lighting a match or water and salt