(-44.85,5.3) and (4.85,3.5) what is the slope

Mathematics

2 answers:

Airida [17]2 years ago

4 0

Find the change in Y over the change in X

$\frac{y2 - y1}{x2 - x1}$

Grace [21]2 years ago

4 0

Answer:

The slope is 0.036 (to the nearest thousandth)

Step-by-step explanation:

We need to determine by how much both x and y change as we go from (-44.85,5.3) to (4.85,3.5). It might help to write out what we have here:

4.85

- ( -44.85)

-----------------

49.7 This is the increase in x. Note that adding 49.7 to the original -44.85 results in 4.85, as we expect. Meanwhile, y decreases from 5.3 to 3.5, a decrease of 1.8. Thus, the slope of the line passing thru (-44.85,5.3) and (4.85,3.5) is:

m = rise / run = -1.8 / 49.7 = 0.0362 (to the nearest 10 thousandth), or 0.036 (to the nearest thousandth), or 0.04 (to the nearest hundredth).

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3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$