Three elements that are likely to have similar chemical and physical properties are
Answer:
It is possible she could get one.
Explanation:
To solve this problem we need to convert 98.3 kilometers/hour to miles/hour.
In other words, we <u>convert km to mi</u>, to do so we multiply 98.3 km by a <em>conversion factor</em>, putting the unit we want to have in the numerator, and the unit we want to convert in the denominator:
- 98.3 km * = 61 mi
Given that the little old lady is doing 61 miles/hour, she could get a speeding ticket.
Answer:
49.5J/°C
Explanation:
The hot water lost some energy that is gained for cold water and the calorimeter.
The equation is:
Q(Hot water) = Q(Cold water) + Q(Calorimeter)
<em>Where:</em>
Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J
Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J
That means the heat gained by the calorimeter is
Q(Calorimeter) = 4794J - 3834J = 960J
The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:
59.4°C-40°C = 19.4°C
And calorimeter constant is:
960J/19.4°C =
<h3>49.5J/°C</h3>
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Answer:
Constant pressure
Explanation:
At constant pressure,
At constant temperature,
1 mol of an ideal gas at STP has a volume of 22.71 L.
Let's compare the work done as it expands under each condition from an initial volume of 22.71 L.
Isobaric expansion
A plot of -w vs V₂ gives a straight line (red) with a constant slope of 100 J/L as in the diagram below (Note that w is work done on the system, so -w is the work done by the system).
\
Isothermal expansion
A plot of -w vs V₂ is a logarithmic curve. Its slope starts at 100 J/mol but decreases as the volume increases (the blue curve below).
Thus, the work done during an expansion at constant pressure is greater than if the system is at constant temperature.