I need help with this I am giving 60 points

Mathematics

1 answer:

inna [77]2 years ago

3 0

Answer:

<2 ≅<4 with reason of vertical angle theorem.

Step-by-step explanation:

The vertical angle theorem states that two opposite (non-adjacent) angles formed by 2 intersecting lines have equal measure. In this problem, we are given that the angles are vertical angles. So the statement is that <2 ≅<4 with reason of vertical angle theorem.

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Giving brainliest to the answer who gives step by step examples clearly!

Anarel [89]

Hi there!

This should be easy,lol!

Answer:

$\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }$ (Decimal: -221.702503)

$\sqrt[3]{162} = \boxed{162 \sqrt{3} }$ (Decimal: 280.592231)

$\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}$

Sorry bout the explanation thingy. Their really long -.-!

But the last one is short so i'll put it for you!

Step-by-step explanation:

∴!For the last one!∴

$\sqrt[3]{-1000x^4}$

Simplifies to:

$= - 1732.050808 * x^4$

$= - 1732.050808 * ( x * x * x * x)$

$= - 1732.050808x^4$

Have a great day/night!

7 0

2 years ago

Read 2 more answers

Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)

Elina [12.6K]

So hmm check the picture below

the height or altitude is CD
and the base is AB

how long are those? well $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 6}}\quad ,&{{ 0}})\quad 
% (c,d)
B&({{ 1}}\quad ,&{{ 5}})\\\\
C&({{ 2}}\quad ,&{{ 0}})\quad 
% (c,d)
D&({{ 4}}\quad ,&{{ 2}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
AB=\sqrt{(1-6)^2+(5-0)^2}\qquad \qquad CD=\sqrt{(4-2)^2+(2-0)^2}$