Relative dating is used to arrange geological events, and the rocks they leave behind, in a sequence. The method of reading the order is called stratigraphy (layers of rock are called strata). Relative dating does not provide actual numerical dates for the rocks.
The correct answer is A I believe
Solution:
4.2 x 10^6 bp/10^3 bp/seconds = 4.2 + 103 s which is 4200 seconds and equivalents to 70 minutes
In addition, assuming a pause of 2 seconds for re initiating after completing every okazaki fragment and assuming the okazaki fragments average 1000 nucleotide long.
4.2 x 10^6 bp/10^3 bp = 4200 okazaki fragments 4200 * 2 seconds = 8400 seconds which is 140 minutes or 2 hours 20 minutes of pauses alone.
Therefore, overall time would be pauses plus the 70 minutes so total time of 210 minutes. Assuming that the replisome completely disassociates from the DNA after every okazaki fragment and must spend one-minute rebinding.
4200 okazaki fragments. 60 seconds rebinding time per fragment: 4200 x 1 minute = 4200 minutes rebinding time plus 70 minutes for actual replication. 4200 minutes is 70 hours which is almost 3 days.
Answer:
More individuals are produced each generation that can survive. Phenotypic variation exists among individuals and the variation is heritable. Those individuals with heritable traits better suited to the environment will survive.
Answer:
I think autotrophs by using photosynthesis
Explanation:
