An angle measures 118° less than the measure of a supplementary angle. What is the measure of each angle

During the month of January, an employee earned $6,000 of salary. Withholdings from the employee's salary consist of FICA Social

andrew11 [14]

Answer:

he will earn Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.19132Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.19132Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.19132Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.play.zedarmc.com2859206play.zedarmc.com

Step-by-step explanation:

Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.19132Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.19132Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.19132Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.19132Starfish or sea stars are star-shaped echinoderms belonging to the class Asteroidea. Common usage frequently finds these names being also applied to ophiuroids, which are correctly referred to as brittle stars or basket stars. Starfish are also known as asteroids due to being in the class Asteroidea.play.zedarmc.complay.zedarmc.com285920612860khyytra.aternos.me56249Shelld_smpxyz.aternos.me

7 0

11 months ago

The length of Albert's rectangular are listed below.

trapecia [35]

A. Length - 100 ft Width - 50 ft is the measurement of Tony's backyard.

Albert's Perimeter = 2(l+w) = 2(40+20) = 2(60) = 120 ft.

Tony's Perimeter = 120 ft * 2.5 = 300 ft
Tony's length = 40 ft * 2.5 = 100 ft
Tony's widht = 20 ft * 2.5 = 50 ft

To check tony's perimeter:
P = 2(l + w) = 2 (100 + 50) = 2 (150) = 300 ft.

3 0

2 years ago

Ajay has 170 red ball and 136 green ball.What is the ratio of the red and green balls. best answer will get brainliest mark

Tatiana [17]

I I found the answer, answer is 359 stop answer dear

5 0

2 years ago

You are planning a May camping trip to Denali National Park in Alaska and want to make sure your sleeping bag is warm enough. Th

Goshia [24]

The probability that this bag will be warm enough on a randomly

selected May night at the park is 0.8106 ⇒ answer C

Step-by-step explanation:

You are planning a May camping trip to Denali National Park in Alaska

and want to make sure your sleeping bag is warm enough.

The average low temperature in the park for May follows a normal

distribution

The given is:

1. The mean is 32°F

2. The standard deviation is 8°F

3. One sleeping bag you are considering advertises that it is good for

temperatures down to 25°F (x ≥ 25)

At first let us find the z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean, σ is standard deviation

∵ μ = 32°F , σ = 8°F , x = 25°F

- Substitute these values in the rule

∴ z = $\frac{25-32}{8}=-0.875$

Now let us find the corresponding area of z-score in the normal

distribution table

∵ The corresponding area of z = -0.875 is 0.18943

∵ For P(x ≥ 25) the area to the right is needed

∵ P(x ≥ 25) = 1 - 0.18943 = 0.8106

∴ P(x ≥ 25) = 0.8106

The probability that this bag will be warm enough on a randomly

selected May night at the park is 0.8106

Learn more:

You can learn more about mean and standard deviation in brainly.com/question/6073431

#LearnwithBrainly

3 0

2 years ago

Certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours. Find the probabi

Anna71 [15]

Answer:

Step-by-step explanation:

given that certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours.

Sample size n =16

Std error of sample mean = $\frac{\sigma}{\sqrt{n} } \\= 15$

x bar follows N(800, 15)

the probability that a random sample of 16 tubes taken from the group will have a mean lifetime

(a) between 790 and 810 hours,

= $P(790$

(b) less than 785 hours

$=P(X$

, (c) more than 820 hours,

$=P(X>820)\\=p(Z>1.333)\\= 0.0913$

(d) between 770 and 830 hours

= $P(|Z|$

4 0

2 years ago