Answer:
y=.5 or y=1/2
Step-by-step explanation:
3(0)+2y=1
3 x 0 = 0
0 + 2y = 1
2y = 1
Divide by 2
y=.5 or y=1/2
Answer:
66ft
Step-by-step explanation:
c=pixD
c=pix21
c=65.9...=66ft
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:
P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:
P = 0.59
Answer:
The first row
Step-by-step explanation:
Letters A,B,C,D
Es la segunda media es 1.65, mediana es 1.65, y modo es 1.61