Answer:
Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)
x coordinate of point c = a
N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)
M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)
MA = √(3a / 2 - 0)² + b / 2 - 0)²
= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4
NB = √(a / 2 - 2a)² + (b / 2 - 0 )²
= √( a / 2 - 4a / 2)² + (b / 2 - 0)²
= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4
Step-by-step explanation:
I tried my best hope its correct :0
It would be a special purposes map :)
(3³ x 5³)² - 2
( 27 x 125)² - 2
125 x 27 = 3375
3375² = 11,390,625
11,390,625 - 2 = 11,390,623
Answer:
x ≈ 2879.4 m
Step-by-step explanation:
Measure of ∠DAC = 10°
Measure of ∠DAB = 90°
Measure of ∠BAC = 90° - 10° = 80°
By applying cosine rule in ΔABC,
cos(80°) = 
= 
0.17365 = 
x = 
x = 2879.36
x ≈ 2879.4 m
Hey there! :)
Answer:
C.
Step-by-step explanation:
For a graph to have a change in amplitude, there must be a coefficient in front of the equation, or the 'a' value.
Recall that the transformation form of a trigonometric graph is:
y = ±a(cos(b(x-h))+k
Where 'a' is the amplitude
'b' changes the period
'h' is a horizontal shift
'k' is a vertical shift
We can look at each choice and eliminate:
A. There is only a coefficient of -1 in front of the equation, which simply results in a reflection over the x-axis. This is incorrect.
B. This equation contains a b value of 2. This changes the period of the graph, not the amplitude. This is incorrect.
C. This equation contains a coefficient, or 'a' value of -2. The amplitude is changed by a factor of 2. This is correct.
D. This graph only contains a vertical shift of 1 unit up. This is incorrect.
Therefore, C is the correct answer.
