Answer:
so i think it is rst on the right
1. the answer is 24. think of x as the original amount, and y as the new amount. y times 1.5 is x, and y+12 is x. reverse that to figure out y, which is what we need, and you have x/1.5 = y as well as x-12 = y. Use the equal values method and make an equation x/1.5=x-12. solve this equation to get x, which is 36. to figure out the new amount, y, you need to subtract 12, which would help you get 24 as your final answer.
2. once again, create an equation. let's call team 1 x and team 2 y. team one has 1/4th as many as team 2, so that would be x=1/4y. An easier way to write that is 4x=y. after 6 people quit team two, that would be y-6. after the transfer, that would be y-6-12, and x+12 for the teams. they are equal after these, so y-6-12=x+12. solve this equation to get y-18= x+12. if you recall earlier, y was 4 times x, so substitute that into y to get 4x-18=x+12. Solve the equation to get 10 people on team one originally. your final answer is 10 people.
2 3/4 divided by 1/4
is
2 3/4 multiplied by 4/1
which is (2+3/4)*4 = 2*4 + 3/4*4 = 8+3 =<em>11</em>
9514 1404 393
Answer:
- 85 ones
- 70 fives
- 15 tens
- 2 fifties
Step-by-step explanation:
Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us ...
a +5b +10c +50d = 685 . . . . . total amount of cash
b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens
a = b+c . . . . . . . . . . . as many ones as fives and tens combined
d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills
__
Substituting for 'a', then for 'b', we have ...
(b+c) +5b +10c +50d = 685
6(10 +4c) +11c +50d = 685
60 +35c +50d = 685
Substituting d=2 and subtracting 160 gives ...
35c = 525
c = 15
b = 10 +4c = 10 +4(15) = 70
a = b+c = 70 +15 = 85
The register contained ...
- 85 ones
- 70 fives
- 15 tens
- 2 fifties
