Answer:
"where deliberately discarded solid waste is discharged, deposited, injected, dumped, spilled, leaked, or placed so that such solid waste or a constituent thereof may enter the environment or be emitted into the air or discharged into waters, including ground waters."
Explanation:
https://definitions.uslegal.com/s/solid-waste-disposal-site/
Answer:
B. The amounts of water and alcohol are not the same
Explanation:
The computation for molarity is:
(x) (0.175 L) = 0.0358 g / 598 g/mol
x = 0.000342093 M
Whereas the osmotic pressure calculation:
pi = iMRT
pi = (1) (0.000342093 mol/L) (0.08206 L atm / mol K) (298 K)
pi = 0.0083655 atm
Converting the answer to torr, will give us:
0.0083655 atm times (760 torr/atm) = 6.35778 torr
which rounds off to 6.36 torr
To solve this, we simply equate the change in enthalpy for
the two substances since heat gained by water is equal to heat lost of aluminum.
We know that the heat capacity of aluminum is 0.089 J/g°C and that of water is
4.184 J/g°C. Therefore:
450.2 (95.2 - T) (0.089) = 60 (T – 10) (4.184)
3,814.45456 – 40.0678 T = 251.04 T – 2,510.4
291.1078 T = 6,324.85456
<span>T = 21.7°C</span>