Write an equation in slope-intercept form that has m = 5/4 through (-4,-3)

Mathematics

1 answer:

timama [110]2 years ago

4 0

Answer:

y=5/4x + 2

Step-by-step explanation:

Ok so in the point (-4,-3) -4 is x and -3 is y. Now, since you have the slope, 5/4, you can put it into an equation. -3= 5/4(-4) + b. When you multiply 5/4 x -4 you get -3=-5 + b so then add 5 to both sides to get rid of it and you have 2=b. And your equation would be y=5/4x + 2

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nikitadnepr [17]

Answer:

y = (1/4)x - 3

Step-by-step explanation:

The slope-intercept form is y = mx + b. Here we are told that the line passes through (-8, -5) and that its slope is 1/4 (is that correct?).

Substituting -5 for y, -8 for x and 1/4 for m, we get an equation for the y-intercept, b:

-5 = (1/4)(-8) + b, or

-5 = -2 + b, so b = -3, and the desired equation is

y = (1/4)x - 3

3 0

2 years ago

R + s² at r = 4, s = 1 ( Pls show work) AND NO LINKS THX UwU

icang [17]

r+s^2

4+1^2

4+2

Hopefully this helped

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5 0

2 years ago

Given the three vertices W(−1, 4), X(−3, −2), and Y(3, −4), what are the coordinates of Z that make quadrilateral WXYZ a square?

prohojiy [21]

Answer:

I don't see how the three existing points could ever become a square with the addition of a foiurth point.

Step-by-step explanation:

See the attached image.

A square would require that all angles be 90 degrees. The given points are the top three points on the graph. If we enter the two equations that intersect these points (blue and black lines), we can see that the angle on top is not 90 degrees. I can't see that this could ever be a square with a fourth point, z. I did find a value for z that make the four points a parallelogram.