Given the three vertices W(−1, 4), X(−3, −2), and Y(3, −4), what are the coordinates of Z that make quadrilateral WXYZ a square?
1 answer:
Answer:
I don't see how the three existing points could ever become a square with the addition of a foiurth point.
Step-by-step explanation:
See the attached image.
A square would require that all angles be 90 degrees. The given points are the top three points on the graph. If we enter the two equations that intersect these points (blue and black lines), we can see that the angle on top is not 90 degrees. I can't see that this could ever be a square with a fourth point, z. I did find a value for z that make the four points a parallelogram.
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Answer:
242 integers
Step-by-step explanation:
We have to find the number of integers between 17 and 2678 which are the multiple of 11.
Divide 17 by 11 =
Smallest multiple of 11 which is greater than 11 = 2nd multiple = 22
Divide the largest number 2678 by 11 =
Largest multiple of 11 which is less than 2678 = 443rd multiple
= 243 × 11
= 2673
Therefore, number of integers between 17 and 2678 multiple of 11
= 243 - 2 + 1
= 242 integers