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2 years ago

Combining like terms with negative coefficients and distribution -5(3x+10)-2(4x-5) ?

Mathematics

1 answer:

N76 [4]2 years ago

5 0

Answer:

-23x-40

Step-by-step explanation:

-5(3x+10)-2(4x-5)
-15x-50-8x+10
-23x-40

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2. Find the value of root4 (81)-2

arlik [135]

<h2>Answer: 1</h2>

Step-by-step explanation:

$\sqrt[4]{81} -2\\=3-2 \\=1$

6 0

1 year ago

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

2 years ago

What is the volume of the prism? ft3 1 12 ft 6 ft 8 ft

zavuch27 [327]

V=lwh

V=8×12×6=576 ft³

Answer: V=576 ft³

7 0

2 years ago

Find the area of the triangle

Svetradugi [14.3K]

A = LW

A = 28 × 7.1

A = 198.8

The correct answer is A.

4 0

2 years ago

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The length of a rectangular playing field is 5m longer than its width. If the perimeter of the field is 150m,find it's width

Inessa05 [86]

Answer:

Step-by-step explanation:

Make equations, l = w+5 and 2l + 2w = 150

Substitute w+5 into 2l + 2w = 150

Simplify to get 4w + 10 = 150

Subtract 10 from both sides to get 4w = 140

Divide both sides by 4 and you get 35 as width

5 0

2 years ago

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