It will be secx = 2
or, cosx = 1/2
or x = Π/3 , 5Π/3
Answer:
x < 33.84
Step-by-step explanation:
we have
13.48x-200 < 256.12
Solve for x
Adds 200 both sides
13.48x-200 +200 < 256.12+200
13.48x < 456.12
Divide by 13.48 both sides
13.48x/13.48 < 456.12/13.48
x < 33.84
The solution is the interval ----> (-∞, 33.84)
All real numbers less than 33.84
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Answer: they had a bad reputation
Step-by-step explanation:
Answer:
absolute max is 120 and absolute min is -8
Step-by-step explanation:
Find critical numbers
f'(x) = 3x^2 - 12x + 9 = 0
= 3(x^2 - 4x + 3) = 0
3(x-3)(x-1) = 0
(x-3) = 0 or (x-1)=0
x = 1,3
Test them!
x<1 Sign of f' on this interval is positive
1<x<3 Sign of f' on this interval is negative
x>3 Sign of f' on this interval is positive
f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.
f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.
Test the endpoints to find the absolute max and min.
f(-1) = -8
f(1) = 12
f(3) = 8
f(7) = 120
The absolute maximum value of f is 120 and the absolute minimum value of f is -8.
