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2 years ago

A driving moving at 22m/s stops the car in 2s. find the stopping distance

Mathematics

1 answer:

Kaylis [27]2 years ago

8 0

Step-by-step explanation:

Hey there!

Here,

Speed = 22m/s

Time = 2 s.

Distance = ?

We have;

$d = s \times t$

$d = \frac{22m}{s} \times 2 \: s$

Cancel "s" and multiply 22 to 2 ,we will get;

Distance = 44m.

Therefore, distance = 22m.

Hope it helps..

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The average score of all golfers for a particular course has a mean of 65 and a standard deviation of 4.5 . Suppose 81 golfers p

Natali5045456 [20]

Answer:

Answer:

The probability that the average score of the 49 golfers exceeded 62 is 0.3897

Step-by-step explanation:

6 0

2 years ago

Invested 28, 000 in two accounts, one yielding 8% and the other at 9%. If i receive a total of 2,440 in intrest at the end of th

dalvyx [7]

Answer:

8,000 in the 8% account

20,000 in the 9% account.

Step-by-step explanation:

x + y = 28000

0.08 x + 0.09 y = 2440

0.08 x + 0.09 (28000 − x) = 2440

0.08 x + 2520 − 0.09 x = 2440

80 = 0.01 x

x = 8000

y = 20000

8 0

2 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the

zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Past studies suggest this proportion will be about 0.15

This means that $p = 0.15$

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}$

$\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}$

$(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}$

$n = 17.5$

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

8 0

2 years ago

Write the equation of the line that is parallel to y =- 2x + 5 and goes through the point (2, -3)

algol [13]

Answer:

y = -2x + 1

Step-by-step explanation:

Parallel lines are two lines that have the same plane and slope but never intersect.

8 0

2 years ago

Use r =27 & x =3 <img src="https://tex.z-dn.net/?f=-%5Cfrac%7Br%7D%7B9%7D%2B%205x" id="TexFormula1" title="-\frac{r}

MrRa [10]

Answer:

Step-by-step explanation:

First substitute the equation with the variable replacements given:

-r/9 + 5x <--- Before

-27/9 + 5(3) <--- After

Next Solve the parts of the Equation

-27/9 + 5(3)

-3 + 15 <--- -27 divided by 9 is -3, 5 times 3 is 15.

= 12 <--- 15 - 3 = 12.

I hope this helps!

4 0

2 years ago

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