Find the sum 1/b^2c +b/c^2
1 answer:
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Answer: y = -4/3x + 0. Yes, that point lies on the line
Step-by-step explanation:
Use this equation, Δy/Δx and this one, y = mx + b. Or, change in the y value divided by the change in the x value.
-4 + 8 = 4
3 - 6 = -3
The slope, m, is -4/3. Now solve for b by plugging in the slope.
. B is equal to 0
To see if that point lies on the function, plug it in the equation and see if it is true. Multiply -4 x -3 to get 12, divide by 3 to get 4, then add 0. The equation says that 4 = 4, which is infact true