Please help asap calculate the slope of the line through the points (6,-8) and (3,-4).
2 answers:
Answer: y = -4/3x + 0. Yes, that point lies on the line
Step-by-step explanation:
Use this equation, Δy/Δx and this one, y = mx + b. Or, change in the y value divided by the change in the x value.
-4 + 8 = 4
3 - 6 = -3
The slope, m, is -4/3. Now solve for b by plugging in the slope.
. B is equal to 0
To see if that point lies on the function, plug it in the equation and see if it is true. Multiply -4 x -3 to get 12, divide by 3 to get 4, then add 0. The equation says that 4 = 4, which is infact true
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Answer:
P = 9 is the max value
Step-by-step explanation:
Sketch
2x + 4y = 10
with x- intercept = (5, 0) and y- intercept (0, 2.5)
x + 9y = 12
with x- intercept = (12, 0) and y- intercept = (0, )
Solve
2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)
The region corresponding to the solution of the system of constraints
Has vertices at (0, ), (0, 0) , (5, 0) and (3, 1)
Now evaluate the objective function at each vertex.
(0, 0) can be excluded as it will not give a maximum
(5, 0) → P = 5 + 0 = 5
(0, ) → 0 + 8 = 8
(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value
Thus the maximum value is 9 when x = 3 and y = 1