Assuming that all energy of the small ball is transferred
to the bigger ball upon impact, then we can say that:
Potential Energy of the small ball = Kinetic Energy of
the bigger ball
Potential Energy = mass * gravity * height
Since the small ball start at 45 cm, then the height
covered during the swinging movement is only:
height = 50 cm – 45 cm = 5 cm = 0.05 m
Calculating for Potential Energy, PE:
PE = 2 kg * 9.8 m / s^2 * 0.05 m = 0.98 J
Therefore, maximum kinetic energy of the bigger ball is:
<span>Max KE = PE = 0.98 J</span>
Answer:
t = 180 / 1.4 = 129 sec (time to swim horizontally across river)
S = 129 sec * V where V is speed of current and S is the distance he will be carried downstream
The problem does not specify V the speed of the river
So we want to know what changes inside the multimeter when we change the voltage range from 200 V to 20 V, by what factor and does it increase or decrease. What we want when trying to measure the voltage with a multimeter is that a minimal current passes trough the mulitmeter so when we change the voltage range, we decrease the resistance by a factor of 10 because the voltage is decreased by a factor of 10.
The characteristics of the projectile launch allows to find the results for the questions about the movement of the ball are:
-
In the attached we see the vertical speed decreases with height and the curve is of the parabolic type.
- In the movement is several dimensions, each one is independent of the others, the movement in the x axis does not affect the movement in the y axis.
Kinematics studies the motion of bodies looking for relationships between position, velocity and acceleration. In the case of vertical and projectiles launch the acceleration on the vertical axis is the acceleration of gravity directed downward.
In the attachment we can see the position of the ball for two distances in the case of projectile launching.
We can see that the speed of the ball decreases with height according to the relation
y = go t - ½ g t²
Where y is the height, g is the initial vertical velocity, g is the acceleration of gravity and t is time.
In all movements in various dimensions we assume that each movement in an .
axis is independent
In the case of projectile launching, on the vertical axis there is an acceleration of gravity and on the horizontal axis there is no acceleration, the only parameter that this gives the two movements is the time, which is a scalar.
In conclusion, using the characteristics of the projectile launch, we can find the results for the questions about the movement of the ball are:
- In the movement is several dimensions, each one is independent of the others, the movement in the x axis does not affect the movement in the y axis.
- In the attached we see the vertical speed decreases with height and the curve is of the parabolic type.
Learn more about projectile launch here: brainly.com/question/24888457
Answer:
Explanation:
The given time is 1 / 4 of the time period
So Time period of oscillation.
= 4 x .4 =1.6 s
When the block reaches back its original position when it came in contact with the spring for the first time , the block and the spring will have maximum
velocity. After that spring starts unstretching , reducing its speed , so block loses contact as its velocity is not reduced .
So required velocity is the maximum velocity of the block while remaining in contact with the spring.
v ( max ) = w A = 1.32 m /s.