The force needed to keep the space shuttle moving at constant speed is 0.
The given parameters;
- <em>weight of the space shuttle, F = 750,000 N</em>
- <em>constant speed of the space shuttle, v = 28,000 km/h</em>
The mass of the space shuttle is calculated as follows;
The force needed to keep the space shuttle moving at constant speed is calculated as follows;
where;
a is the acceleration of the space shuttle
At a constant speed, acceleration is zero.
F = 76,530.61 x 0
F = 0
Thus, the force needed to keep the space shuttle moving at constant speed is 0.
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The acceleration of the car is solved by subtracting the initial speed from the final speed then dividing the result by the elapsed time.
initial speed = 72 km/hr = 20 m/s
final speed = 0 m/s
elapsed time = 5 seconds
acceleration = (0 m/s – 20 m/s) / 5 s
acceleration = - 20m/s / 5 s
acceleration = -4 m/s^2
Answer:
Flow rate 2.34 m3/s
Diameter 0.754 m
Explanation:
Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.
The area at the well head is
So the volume flow rate along the pipe is
We can use the similar logic to find the cross-section area at the refinery
The radius of the pipe at the refinery is:
So the diameter is twice the radius = 0.38*2 = 0.754m
Answer:
The hypothesis may or may not be true and needs to be tested. It might be the answer to the problem. Hence, it must be tested thoroughly. When these predictions are tested again and again in independent scientific experiments and gets verified, the hypothesis is converted into a scientific theory.