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2 years ago

The total magnification of a specimen being viewed with a 10X ocular lens and a 40X objective lens is _____.

Physics

1 answer:

raketka [301]2 years ago

3 0

Answer:

total magnification = 400 X

Explanation:

given data

ocular lens = 10 X

objective lens = 40 X

to find out

total magnification

solution

we know that total magnification is express as

total magnification = Objective magnification × ocular magnification .................1

put here value we get

total magnification = 10 × 40

total magnification = 400 X

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Lifting book over your head is what type of energy

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Answer:

potential energy

Explanation:

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2 years ago

Which of the following statements about the impact of biotechnology on the environment is not true?

Vladimir79 [104]

E) Biotechnology use can lead to an increase in soil erosion and pollution runoff through decreased pesticide use.

Explanation:

Biotechnology use cannot lead to an increase in soil erosion and pollution runoff through decreased pesticide use.

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2 years ago

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How does the magnitude of the electrical force between a pair of charged particles change when they are brought to half their or

Ostrovityanka [42]

Answer:

5. Quadruple

Explanation:

The electrostatic force between two charged particles is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the charges

If the distance between the charges is reduced to half,

$r' = \frac{r}{2}$

So the new force will be

$F'=k\frac{q_1 q_2}{(r/2)^2}=4(k\frac{q_1 q_2}{r^2})=4F$

So, the force will quadruple.

4 0

2 years ago

1. Ramon puts two magnetic toy trains very close to each other on a track. What will happen next, and

FrozenT [24]

Answer:

If one side of the train is positive and the other is negative they will attract if they are the same then they will repel.

Explanation:

If both are positive they will repel if both are negative they will repel and if they are opposites they will attract.

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2 years ago

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A toy rocket is launched with an initial velocity of 12.0 m/s in the horizontal direction from the roof of a 30.0-m-tall buildin

OlgaM077 [116]

Solution :

The motion in the y direction.

The time taken by the toy rocket to hit the ground,

$S=ut+\frac{1}{2}at^2$

S = distance travelled = 30 m

u = 0 m/s

a = $9.8 \ m/sec^2$

t= time in seconds

Therefore, $30 =\frac{1}{2}9.8 t^2$

t = 2.47 sec

Now motion in the x direction,

u = 12 m/sec

$a=1.6 t \ m/sec^3$

Upon integration 'v' with respect to 't'

$v=\frac{1.6t^2}{2}+12$

Once again integrating with respect to t,

$s=\frac{1.6t^3}{6}+12 t$

$s=\frac{1.6(2.47)^3}{6}+12 (2.47)$

= 0.0176+29.64

= 29.65 m

Therefore, the toy rocket will hit the ground at 29.65 m from the building.

7 0

2 years ago