Clouds and fog and it may rain or snow
Halitic rocks have a large mineral layer of evaporite sedimentary rock, which is produced from drained lakes, playa and closed seas.
The difference between Halit rock layers and other rock layers is the element in it. The element in the Halit rock layer is sodium chloride.
<h2>Further explanation
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Halit Rock Layer is a type of salt, a mineral form (natural) from sodium chloride (NaCl) or better known as rock salt.
Knowledge about the layers of soil and rocks on the surface of the earth is stratigraphy. Stratigraphy is the study of the history, composition and relative age and distribution of bedding layers and the interpretation of rock layers to explain the history of the Earth.
Learn More
- Sodium chloride (NaCl) brainly.com/question/7007192
- stratigraphy brainly.com/question/12372481
Details
Class: Middle School
Subject: Physics
Keywords: Rock Layer, Halit Rock, Stratigraphy
As the speed of the plunger increases, the wavelength of the waves decreases. The greater the frequency, the smaller the wavelength. The smaller the frequency, the greater the wavelength. When we increase the speed of the plunger, the frequency of the waves also increases, and just like with the size of the ball, it’s the speed of the plunger and the frequency of the waves are directly related.
There is not a "for sure" answer yet, but scientist thinks that it might be due to Saturn's cloud cover, if the cloud cover fluctuated, then Saturn would scatter infrared light differently, giving off more energy than it needs to.
Answer:
the cat is 0.4238 m in front of the dog as it leaps through the window
Explanation:
Given that;
acceleration a = 0.85 m/s²
speed v = 1.40 m/s
the cat is at rest, so initial velocity u = 0
we know that, since the cat is sleeping on the floor in the middle of a 2.8-m-wide room, it needs to cover (2.8 m / 2 ) distance to get to the window;
using the second equation equation of motion;
s = ut + 1/2 at²
we substitute
2.8/2 = 0×t + 1/2 × 0.85 × t²
1.4 = 0.425t²
t = √( 1.4 / 0.425 )
t = 1.81497 sec
now, at acceleration 0.10 m/s²
the dog has to cover the distance;
s = ut + 1/2 at²
s = ( 1.4 × 1.81497) - 1/2 × 0.10 × 1.81497²
s = 2.540958 - 0.1647
s = 2.3762 m
The cant in front of the dog as it leaps through the window;
distance = 2.8 m - 2.3762 m
distance = 0.4238 m
Therefore, the cat is 0.4238 m in front of the dog as it leaps through the window
