The probability that you will wait for at most 5 seconds is 6.7%
<h3>How to determine the probability?</h3>
The given parameters are:
Green = 40
Yellow = 5
Red = 30
When you spend a maximum of 5 seconds, it means that you get to the traffic light at the yellow cycle.
The probability is then calculated as:
P(Yellow) = 5/(40 + 5 + 30)
Evaluate
P(Yellow) = 6.7%
Hence, the probability that you will wait for at most 5 seconds is 6.7%
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Answer: 0.25g<2.50.... g<10
Step-by-step explanation: Let us say that the number of gumballs bought is represented by the variable g. In this case, the question is asking how many gumballs can be bought without surpassing the price of $2.50. We know that each gumball is $0.25, therefore the number of gumballs we buy times $0.25 has to be less than $2.50. Hence, the inequality would be 0.25g<2.50. If we were to solve this then g<2.50/0.25-----> g<10. In conclusion, the number of gumballs you can buy has to be less than 10. Thank you!
Answer:
460 rounded to the nearest hundred is 500. 460 rounded to the nearest 10 stays 460.
<em></em>Factors of 52 = 1, 2, 4, 13, 26, 52.
The greatest factor of 52 that is a prime number is 13.
Answer:
lower price = 3
higher price =11
Step-by-step explanation:
p(x) = -2(x-3) (x-11)
Setting equal to zero
0 = -2(x-3) (x-11)
Using the zero product property
x-3 = 0 x-11 =0
x=3 x = 11