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2 years ago

Which of the following represents a relation that is not a function?

Mathematics

1 answer:

Doss [256]2 years ago

7 0

A function is for every input, there is 1 output
aka
x never repeats with a different y

A. x doesn't repeat, it's a function

B. -8 repeats with 34 and 40, this is not a funciton (this is the answer0

C. x doesn't repeat, it's a function

D. x doesn't repeat, it's a function

answer is B

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The point-slope form of the equation of the line that passes through (-9, -2) and (1, 3) is y – 3 = {(x - 1). What is the

Marina86 [1]

Option A is the correct answer, y = x + 2

y - 3 = x-1

If you bring the 3 to the R.H.S, it becomes y = x + 2

If you substitute the values,

3 = 1 + 2

3 = 3

Thus, e equation is correct

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2 years ago

7(4g) + 3(5h) + 2 (-3g); g=1/2 , h= 1/3

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2 years ago

Select the correct answer from each drop-down menu. The given equation has been solved in the table. Step Statement 1 2 3 4 5 Us

stiks02 [169]

Answer:

Is there a picture or something?

6 0

1 year ago

Rewrite the following quadratic functions in intercept or factored form. Show your work.

Vlad [161]

Answer:

y = (2x + 3)(2x + 3) = (2x + 3)²

Step-by-step explanation:

We are given a quadratic function and we have to write it in factored form.

y = 9 + 12x + 4x²

y = 4x² + 12x + 9

We can break the mid-term in such a way that when they are multiplied, the factors give a product of 36x² and when added, they give a result of 12x, as show below:

y = 4x² + 6x + 6x + 9

Taking 2x common from the first two variables and 3 from the second two

y = 2x(2x + 3) + 3(2x + 3)

Taking 2x+3 common

y = (2x + 3)(2x + 3) = (2x + 3)²

3 0

2 years ago

Read 2 more answers

An investor invested a total of $2,800 in two mutual funds. One fund earned 5% profit while the other earned 3% profit. If the i

8_murik_8 [283]

The amount invested in the mutual fund that earned 5% is $ 1000

The amount invested in the mutual fund that earned 3% is $ 1800

<h3><u>Solution:</u></h3>

Given that , An investor invested a total of $2,800 in two mutual funds

Let the amount invested in 1st mutual fund be $n

Then the amount invested in the other mutual fund will be $(2800 - n)

One fund earned 5% profit while the other earned 3% profit

Then, profit earned by 1st fund ⇒ 5% of n

And profit earned by 2nd fund ⇒ 3% of 2800 – n

Investor's total profit was $104

Now, we know that,

<em>total profit = profit earned on 1st fund + profit earned on 2nd fund </em>

104 = 5% of n + 3% of ((2800 - n)

$\frac{5}{100} n+\frac{3}{100}(2800-n)=104$

$\begin{array}{l}{\frac{5 n+3(2800-n)}{100}=104} \\\\ {5 n+3 \times 2800-3 n=10400} \\\\ {5 n-3 n=10400-8400} \\\\ {2 n=2000} \\\\ {n=1000}\end{array}$

So, he invested $ 1000 in 1st fund at 5 % profit

And 2800 – n = 2800 - 1000 = $ 1800 in 2nd fund at 3 % profit

4 0

3 years ago