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2 years ago

7(4g) + 3(5h) + 2 (-3g); g=1/2 , h= 1/3

Mathematics

1 answer:

Digiron [165]2 years ago

4 0

7(4(1/2))+3(5(1/3))+2(-3(1/2))=
7(4/2)+3(5/3)+2(-3/2)=
7(2)+15/3+-6/2=
14+5-3=
19-3=
16

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If a/4 = 9/a, then<br> a²=36<br> 4a = 9a<br> a + 4 = 9 + a<br> a - 4 = 9 - a

Anna [14]

Answer:

Option A is correct.

The given expression : $\frac{a}{4} = \frac{9}{a}$ then;

$a^2 = 36$

Step-by-step explanation:

Given the expression: $\frac{a}{4} = \frac{9}{a}$

Cross multiplication the given expression following steps are as follow;

Multiply numerator of the left-hand fraction by the denominator of the right-hand fraction

Also, Multiply numerator of the right-hand fraction by the denominator of the left-hand fraction.

then, set the two products equal to each other.

Using cross multiplication, on the given expression;

$\frac{a}{4} = \frac{9}{a}$

First multiply the numerator of the left hand fraction(i.e,a ) by the denominator of the right hand fraction (i,e a)

we have;

$\frac{a \times a}{4} = 9$

Simplify:

$\frac{a^2}{4} =9$ [1]

now, multiply numerator of the right-hand fraction( i.e, 9) by the denominator of the left-hand fraction (i.e, 4 ) in [1]

we have;

$a^2 = 9\times 4$

Simplify:

$a^2 = 36$

Therefore, the given expression is equal to: $a^2 = 36$

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Help please asap . please explain your answer

vesna_86 [32]

Answer:

y = -6x + 2

Step-by-step explanation:

Slope intercept form: y = mx + b

m is the slope

b is the y-intercept

The line pictured goes down 6 for each 1 it moves to the right, slope is rise over run, in this case, -6/1 or just -6

The y-intercept is the point that the function crosses the y-axis, in this case 2

Plug those in to get:

y = -6x + 2

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Please help I’ll give brainliest

wolverine [178]

Answer:

y=1/2×+4

Step-by-step explanation:

i think that the answer

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The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.

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$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=-5\\ n=10\\ a_{10}=13 \end{cases} \\\\\\ a_{10}=a_1+(10-1)d\implies 13=-5+(10-1)d \\\\\\ 13=-5+9d\implies 18=9d\implies \cfrac{18}{9}=d\implies \boxed{2=d}$

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