The volume of the pyramid with the given length, width and height is 165in³.
<h3>What is the volume of the pyramid?</h3>
The volume of a right rectangular pyramid is expressed as;
V = ( L × W × H ) / 3
Given that;
- Length L = 11in
- Width W = 9in
- Height H = 5in
We substitute into the equation above.
V = ( L × W × H ) / 3
V = ( 11in × 9in × 5in ) / 3
V = 495in³ / 3
V = 165in³
The volume of the pyramid with the given length, width and height is 165in³.
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The formula for the area of a rectangle is A = bh.
Substitute 216.24 for A (area) and 15.9 for h (height).
A = bh
216.24 = b(15.9)
÷ 15.9 ÷ 15.9 Divide 15.9 on both sides.
13.6 = b
So, the base of the rectangle is 13.6 cm.
3. is the answer, as you can see D is one and a half units to the right of the y axis at a height of 3 units and C is one and a half units to the left of the y axis with the same height. So D is "reflected" about the y axis and only the x coordinate changes sign from positive to negative.
11 5/8 + 9 1/2= 21 1/8
3/4 - 2/5= 7/20
4 5/6 - 2 1/2= 2 1/3
I think these are right, I apologize if they are wrong.
