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2 years ago

Find the density of a block with a length of 8.0 cm, a width of 4.0 cm, a height 2.0 cm,

Chemistry

1 answer:

SpyIntel [72]2 years ago

4 0

Answer:

0.80 g $cm^-3$

Explanation:

$\rho=\frac{mass}{volume} \\volume= l \times w \times h = 8.0 cm \times 4.0 cm \times 2.0 cm = 64 cm^3\\\rho = \frac{51 g}{64 cm^3} =$

= 0.80 g $cm^-3$

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Answer:

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2 years ago

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2 years ago

If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?

Pie

Answer:

$m = \frac{E}{c^2}$

$c = \sqrt{\frac{E}{m} }$

$E = 12.8 J$

Explanation:

Part 1: Solving for m

We are given that:

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

$m = \frac{E}{c^2}$

Part 2: Solving for c

We are given that:

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

$c^2 = \frac{E}{m}\\ \\ c=\sqrt{\frac{E}{m}}$

Part 3: Solving for E

We are given that:

m = 80 and c = 0.4

To get the value of E, we will simply substitute in the given equation:

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

4 0

2 years ago