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2 years ago

Light incident on a surface at an angle of 45° undergoes diffused reflection. At what angle will it reflect?

2 answers:

8 0

<span>The correct answer is option D. i.e. at any angle between -90 and 90 degrees. In the diffused reflection ,the surface is rough and the direction of light in not the same as the incident light. It can be reflected at any angle. </span>

Korvikt [17]2 years ago

3 0

Answer:

D. at any angle between -90° and 90°

Explanation:

First of all, we need to understand the difference between specular reflection and diffuse reflection:

- Specular reflection occurs when the surface hit by the light is perfectly smooth. In this case, the law of reflection states that the angle at which the light is reflected is equal to the angle of incidence of the light (measured relative to the normal to the surface)

- Diffuse reflection occurs when the surface hit by the light is rough. In this case, the law of reflection is still valid for every ray of light hitting the surface; however, due to the imperfections of the surface, each ray of light hits the surface at a different angle of incidence. This means that the angle of reflection for each ray will be different, so light is reflected in any direction between -90 degrees and 90 degrees, which corresponds to the minimum and the maximum angle of reflection measured relative the normal to the surface.

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As the amplitude of a mechanical wave increases, which of the following quantities

Lisa [10]

.c ...energy

Explanation:

Amplitude does not affect wavelength. It also does not affect wave speed. Amplitude is the energy of the wave measured from the rest position to the top of the crest. A wave with more energy has a higher up crest/ higher amplitude.

6 0

2 years ago

Volgvan

Answer:

The height is : 60.025 m

Explanation:

The flowerpot falls off the balcony with zero launch angle

Given the time of fright as 3.5 s then ;

The formula to apply is ;

$T=\sqrt{\frac{2H}{g} }\\\\3.5=\sqrt{\frac{2H}{9.8} }$

3.5²= 2H/9.8

12.25 =2H/9.8

12.25 * 9.8 = 2H

120.05 = 2H

120.05/2 = H

60.025 =H

7 0

2 years ago

This is what occurs when matter transitions between solid, liquid and gas.

vodomira [7]

Answer:

The answer is Phase Change

Explanation:

4 0

2 years ago

Read 2 more answers

A heavy meterstick has a mass of 1 kg. When the meterstick is thrown like a spear past you, you measure its momentum to be 2mv.

CaHeK987 [17]

Answer:

Its length is measured to be 0.5 m

Explanation:

From theory of relativity (mass variation), we know that:

m = mo/√(1-v²/c²)

Where, m = relative mass

and, mo = rest mass

The momentum of stick while moving, will be:

P = mv

but, it is given in the form of rest mass as:

P = 2(mo)v

thus, by comparison;

2(mo)v = mv

using value of m from theory of relativity;

2(mo)v = (mo)v/√(1-v²/c²)

√(1-v²/c²) = 1/2 ______ eqn(1)

Now, for relativistic length (L), we have the formula from same theory of relativity;

L = (Lo)√(1-v²/c²)

The rest length (Lo) of meter stick is 1 m, and the remaining term on right side √(1-v²/c²), known as Lorentz Factor, can be given by eqn (1), as equal to 1/2.

Thus,

L = (1 m)(1/2)

4 0

3 years ago

A 2kg block has 70J of KE. It then travels 1.5 meters up a hill. As it travels up the hill friction does -12J of work on the blo

Dima020 [189]

Answer:

v = 5.34[m/s]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the sum of the mechanical energy in the initial state plus the work on or performed by a body must be equal to the mechanical energy in the final state.

Mechanical energy is defined as the sum of energies, kinetic, potential, and elastic.

E₁ = mechanical energy at initial state [J]

$E_{1}=E_{pot}+E_{kin}+E_{elas}\\$

In the initial state, we only have kinetic energy, potential energy is not had since the reference point is taken below 1.5[m], and the reference point is taken as potential energy equal to zero.

In the final state, you have kinetic energy and potential since the car has climbed 1.5[m] of the hill. Elastic energy is not available since there are no springs.

E₂ = mechanical energy at final state [J]

$E_{2}=E_{kin}+E_{pot}$