Mid point = ( 1/2 the sum of x coordinates) , ( 1/2 sum of y coordinates)
= (-42+28)/2 . ( -53 - 19) / 2
= ( -7, -36) Answer
Answer:
In this case, we can do substitution.
Step-by-step explanation:
For the first one, (s - t)(x) = ((x - 5) - 4x^2)(x) = x^2 - 21x
For the second one, (s*t)(x) = ((x - 5) *4x^2)(x) = 4x^4 - 20x^3
And for the last one, (s+t)(-2) = ((x - 5) + 4x^2)(-2) = -8x^2 - 2x + 10
Hope your happy with the answer :)
Answer:
11.31 ft
Step-by-step explanation:
Here in this problem ladder forms a right triangle with the wall of the house and it is acts as hypotenuse, length of one leg of right triangle given to be 4 feet.
Let the ladder reaches x ft height of the house.
Hence, by Pythagoras theorem:
Hence, the ladder reaches 11.31 ft height of the house.
9514 1404 393
Answer:
P = 3x +32
Step-by-step explanation:
If we assume the short vertical edge at top center is 10 yards, as it was in two previous problems with this geometry, then we can find the area of the present parking lot as ...
(x-2)(3x) + x(3x -10) +2x(40) = 6x^2 +64x
where the left vertical rectangle is 3x high and x-2 wide; the center area between vertical rectangles is (2x-2)-(x-2) = x wide and (3x-10) high; and the right vertical rectangle is (x-2 +3x)-(2x-2) = 2x wide and 40 high.
As we said, the right vertical rectangle is 2x wide, so the area that has P as one of its dimensions is ...
A = LW = P(2x)
We want this to be the same as the existing area, so ...
2Px = 6x^2 +64x
P = 3x +32 . . . . . divide by 2x
Answer:
for question 1 it is the first one. and for question 2 it is b
Step-by-step explanation:
i did this already