Answer: 0.3125.
Step-by-step explanation:
- The chance of having a boy is 0.5,
- the chance of having a girl is also 0.5.
<u>Outcome 1: all boys</u>
boy boy boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 2: first child is a girl, all others are boys</u>
girl boy boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 3: second child is a girl, all others are boys</u>
boy girl boy boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 4: third child is a girl, all others are boys</u>
boy boy girl boy
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
<u>Outcome 5: fourth child is a girl, all others are boys</u>
boy boy boy girl
0.5 * 0.5 * 0.5 * 0.5 = 0.0625
Therefore,
0.0625 + 0.0625 + 0.0625 + 0.0625 + 0.0625 = 0.0625 * 5 = 0.3125
Tbh 8778188778654789644477 I’m am a 90 old man
x = 5y - z
You can think that x and z are numbers, and we have one variable z.
x -5y = 5y - 5y - z
x - 5y = - z
(x - 5y)*(-1) = - z *(-1)
z = - x + 5y
<h3>
Answer: 127</h3>
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Explanation:
The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.
The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.
Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.
So we have these scores
- first exam = 70
- second exam = 80
- third exam = 43
- fourth exam = x+5
Adding up these scores and dividing by 4 will get us the average
(sum of scores)/(number of scores) = average
(70+80+43+x+5)/4 = 80
(x+198)/4 = 80
x+198 = 4*80
x+198 = 320
x = 320 - 198
x = 122
So the student got a score of x+5 = 122+5 = 127 on the fourth exam.
Barry's drawing would be 7.6 inches tall and 2.5 inches wide
