The answer is- Part washers use cleaning solutions that eventually become spent and must be disposed of properly.
Cleaning solutions: Cleaning solution is a liquid solvent or solution used to clean the working surfaces and the parts of a machine.
What type of cleaning solution is Part washers?
- Parts washers are mechanical devices that are designed to be cleaned to remove debris, dirt, oil, paint, and other substances that could potentially contaminate parts to prepare them for assembly, packaging, or even painting.
- They are basically used to clean parts to make them ready for functional use.
- Cleaning solutions for washing used parts are considered a special waste because they can be hazardous waste and are waste from an industrial process.
- Used solvents are almost always hazardous waste. Both solvent and aqueous parts washers produce a sludge that is usually hazardous because it contains toxic metals and solvents from the parts being cleaned.
- Absorbents used to wipe parts after washing are also dangerous if they contain toxic metals in concentrations exceeding regulatory limits or listed hazardous solvents, and used oil may also contain hazardous waste.
- Thus, these cleaning solutions must be disposed of properly.
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Answer:
Bonds basically differs with each other due to sharing of electrons .
Explanation:
There are majorly three kinds of bonds
1. Ionic bonds which forms due to an element donate an electron to another element completely .
2. covalent bonds which forms with the mutual sharing of electrons b/w two atoms .
3. metallic bonds which forms b/w metals & they share electrons due to electron negativity difference b/w two atoms or elements
Gamma rays have the highest penetrating power so it can only be stopped by thick layers of dense metal. :)
Option three, starfish is the correct answer since if you draw a line between it, it would be even!
Answer:
12.44 g
Explanation:
2C4H10 + 13O2 = 8CO2 + 10H2O
n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).
n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).
Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.
mass of CO2 produced =
M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol
M = 0.5656/2 * 44
M = 0.2828 * 44
M = 12.44 of CO2
