What is an empirical formula for a compound that is 82.2% nitrogen and 17.8% hydrogen
1 answer:
Percent to mass
Mass to mole
Divide by small
Multiply 'til whole
Assume 100 g of substance, then 82.2 g N and 17.8 g H. 82.2 g N * (1 mol/14.01 g N) = 5.86 mol N 17.8 g H * (1 mol/1.01 g H) = 17.6 mol H Divide by the smallest mole 17.6 H / 17.6 = 1 H 5.86 N / 17.6 = 1/3 N Multiply to make whole number ( x3 in this case) 3 x 1 H = 3H 3 x 1/3 N = 1 N NH3
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