Answer:
160 g of NaOH
Explanation:
Reaction: 2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O
When a base and an acid react, the produce water and a salt. → Neutralization
In this reaction 2 moles of hydroxide need 1 mol of sulfuric acid to react, it is the same to say that 1 mol of sulfuric acid needs 2 moles of NaOH to react. We convert the mass of sulfuric to moles and we propose the rule of three:
196 g / 98 g/mol = 2 moles
1 mol of sulfuric acid needs 2 moles of NaOH to react
Then 2 moles of sulfuric acid will react with (2 . 2) /1 = 4 moles of NaOH
We convert the moles of base to grams → 4 mol . 40 g /1mol = 160 g
Answer:
pH = 12.8
Explanation:
HF + NaOH → F⁻ + Na⁺ + H₂O
<em>1 mole of HF reacts with 1 mole of NaOH</em>
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Initial moles of HF and NaOH are:
HF = 0.018L × (0.308mol / L) = 5.544x10⁻³mol HF
NaOH = 0.023L × (0.361mol / L) = 8.303x10⁻³mol NaOH
That means moles of NaOH remains after reaction are:
8.303x10⁻³mol - 5.544x10⁻³mol = <em>2.759x10⁻³moles NaOH</em>
Total volume is 18.0mL + 23.0mL = 41.0mL = 0.0410L
Molar concentration of NaOH is
2.759x10⁻³moles NaOH / 0.0410L = 0.0673M = [OH⁻]
pOH = - log [OH⁻] = 1.17
As pH = 14 - pOH
<em>pH = 12.8</em>
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4HCl + O₂ → 2Cl₂ + 2H₂O
mole ratio of HCl : O₂ is 4 : 1
∴ if moles of HCl = 2.3 mol
then mol of O₂ = 2.3 mol ÷ 4
= 0.575 mol
mass of O₂ = moles of O₂ × molar mass of O₂
= 0.575 mol × (16 × 2) g/mol
= 18.4 g
Answer:
4HCl + SiO2 → 4H2O + SiCl4
axit clohidric Silic dioxit nước Silic tetraclorua
Axit
Explanation:
<span>All scientists try to base their conclusions on the experiments they have conducted and they have repeated them to be sure of it. </span>