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2 years ago

A helium atom consists of two protons, two

2 answers:

7 0

In the helium atom, the strong force is a fundamental interaction between the "<span>(4) neutrons and protons" and it should be noted that this is the case for most atoms. </span>

alekssr [168]2 years ago

6 0

Answer:

(4) neutrons and protons

Explanation:

there exist four fundamental interaction force as following

1). Gravitational force

2) Electromagnetic force

3). Weak Nuclear force

4). Strong Nuclear force

So here we have to find the strong force between the subatomic particles which will have strongest force

So here all interaction between charge particles are always electromagnetic force which is always weaker than nuclear force

So here we can say that the strongest force will be force between neutrons and protons as the force between them is always strong nuclear force due to which they resides into a small space known as nucleus

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Consider a small frictionless puck perched at the top of a xed sphere of radius R. If the puck is given a tiny nudge so that it

MakcuM [25]

Answer:

Explanation:

Let the vertical height by which it descends be h . Let it acquire velocity of v .

1/2 mv² = mgh

v² = 2gh

As it leaves the surface of sphere , reaction force of surface R = 0 , so

centripetal force = mg cosθ where θ is the angular displacement from the vertex .

mv² / r = mg cosθ

(m/r )x 2gh = mg cosθ

2h / r = cosθ

cosθ = (r-h) / r

2h / r = r-h / r

2h = r-h

3h = r

h = r / 3

5 0

2 years ago

You push very hard on a heavy desk, trying to move it. You do work on the desk:

frozen [14]

Answer:

Explanation:

We know that work done is given by

$W=F.d=Fdcos\Theta$

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

3 0

2 years ago

A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75

Gnom [1K]

Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + ω₂) / 2] × 0.5

But ∇θ = 230 revolutions

∇θ/t = (530 + ω₂) / 2

230 / 0.5 = (530 + ω₂) / 2

Solve for ω₂

460 = 295 + 0.5ω₂

ω₂ = 330rpm

ω₂ = ω₁ + αt

but α = ?

α = (ω₂ - ω₁) / t

α = (330 - 590) / 0.5

α = -260 / 0.5

α = -520rev/min

ω₂ = ω₁ + αt

0 = 590 +(-520)t

520t = 590

solve for t

t = 590 / 520

t = 1.13min

60 seconds = 1min

X seconds = 1.13min

x = (60 × 1.13) / 1

x = 68seconds

∇θ = [(ω₂ + ω₁) / 2] × t

∇θ = [(590 + 0) / 2] × 1.13

∇θ = 333.35 rev/min

8 0

2 years ago

Two friends are playing a version of proton golf where the hole is marked by a single proton. The first friend reads his meter,

yarga [219]

Answer:

the electric field strength on the second one is 2.67 N/C.

Explanation:

the electric fiel on the first one is:

E1 = k×q/(r^2)

r^2 = k×q/(E1)

= (9×10^9)×(q)/(24.0)

= 375000000q

then the electric field on the second one is:

E2 = k×q/(R^2)

we know that R = 3r

R^2 = 9×r^2

E2 = k×q/(9×r^2)

= k×q/(9×375000000q)

= k/(9×375000000)

= (9×10^9)/(9×375000000)

= 2.67 N/C

Therefore, the electric field strength on the second one is 2.67 N/C.

5 0

2 years ago

1.33 m^3 of fluid flows out of a pipe in 24.5 s. the fluid leaves the pipe at 3.55 m/s. what is the area of the pipe. (unit=m^2)

Margaret [11]

Answer:

0.015 $meter^{2}$

Explanation:

Total volume of water coming out = 1.33 $meter^{3}$

Also volume = Cross sectional area*Length covered

Length covered = Velocity *time

=24.5*3.55

=86.97 meter

Let the cross sectional area be A.

1.33 = 86.97*A

A =0.015 $meter^{2}$

3 0

3 years ago

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