Answer:
27.4°C
Explanation:
Using the equation:
Q = m*C*T
<em>Where Q is heat added,</em>
<em>m the mass of water</em>
<em>C specific heat of water (4.18J/g°C)</em>
<em>And T the increase in temperature</em>
We can solve for the increase in temperature and thus, the final temperature of water:
Q = 88200J; m = 6500g:
88200J = 6500g*4.18J/g°C*T
3.2°C = T = increase in temperature
Final temperature is:
24.2°C + 3.2°C =
<h3>27.4°C</h3>
Answer:
V2~0.4839M
Explanation:
We're going to use Boyles law to answer the question.
Boyle's law:
P1V1=P2V2
P1=151mmHg
P2=166mmHg
V1=0.532L
V2=?
V2=(P1 x V1)/P2
V2=(151 x 0.532)/166
V2~0.4839M
Hope it helps:)
POH=14-pH=14-2.5=11.5
pH=-log[H+]
2.5=-log [H+]
[H+]=10^-5/2
[OH-]=10^(14-5/2)=10^23/2
Explanation:
HCL you can do it yourself .try again
Answer:a leech
Explanation: a parasitic relationship is one organism benefit on the other while the other is harmed