Answer:
controlled experiment
Step-by-step explanation:
Controlled experiment is a type of experiment in which except for only one variable, everything is kept constant.
The common type of the controlled experiment compares the control group against the experimental group. All the variables are identical between two groups except factor which is being tested.
Big advantage of the controlled experiment is that one can eliminate much of uncertainty about the results.
Answer:
27.84 m² , 42.48 m²
Step-by-step explanation:
The area (A) of a triangle is calculated as
A = bh ( b is the base and h the perpendicular height )
Shape A
has b = 9.6 and h = 5.8, then
A = 0.5 × 9.6 × 5.8 = 27.84 m²
Shape B
has b = 11.8 and h = 7.2 , then
A = 0.5 × 11.8 × 7.2 = 42.48 m²
Firstly, you want to multiply (f^4)^2.
Next, multiply everything on the numerator.
Next, divide.
Now remember that f^-2 = (1/f^2), so just convert the negative powered exponent to that, and your answer will be
Answer:
a) NORM.S.INV(0.975)
Step-by-step explanation:
1) Some definitions
The standard normal distribution is a particular case of the normal distribution. The parameters for this distribution are: the mean is zero and the standard deviation of one. The random variable for this distribution is called Z score or Z value.
NORM.S.INV Excel function "is used to find out or to calculate the inverse normal cumulative distribution for a given probability value"
The function returns the inverse of the standard normal cumulative distribution(a z value). Since uses the normal standard distribution by default the mean is zero and the standard deviation is one.
2) Solution for the problem
Based on this definition and analyzing the question :"Which of the following functions computes a value such that 2.5% of the area under the standard normal distribution lies in the upper tail defined by this value?".
We are looking for a Z value that accumulates 0.975 or 0.975% of the area on the left and by properties since the total area below the curve of any probability distribution is 1, then the area to the right of this value would be 0.025 or 2.5%.
So for this case the correct function to use is: NORM.S.INV(0.975)
And the result after use this function is 1.96. And we can check the answer if we look the picture attached.