Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:
The solution for f(x) = g(x) are;
x = 1 and x = -1
Step-by-step explanation:
The given equations for the functions, g(x) are;
g(x) = 2 + x
The solution for f(x) = g(x), is given by equating the equations of the two functions as follows;
When f(x) = g(x), we have;
By cross multiplication, we have;
1 + 2·x = x × (2 + x) = 2·x + x²
∴ x² + 2·x - 2·x - 1 = 0
x² - 1 = 0
(x - 1)·(x + 1) = 0
x = 1, or x = -1
f(x) = g(x) = 2 + 1 = 3, or 2 - 1 = 1
Therefore, the solution for f(x) = g(x) are;
f(x) = g(x) = 3 or 1 where x = 1 and x = -1.
The expression to find the number of notebooks James bought would be written as:
Number of notebooks = total spent / cost per item
Number of notebooks = (2y^2 + 6) / <span>(y^2 − 1)
</span><span>If y = 3, then the number of notebooks bought would be:
</span>Number of notebooks = (2y^2 + 6) / (y^2 − 1)
Number of notebooks = (2(3)^2 + 6) / (3^2 − 1)
Number of notebooks = 3 pieces<span>
</span><span>
</span>
We need the cross product of the two vectors.
a x b
=<2,-2,-3> x <3,2,2>
=
i j k
2 -2 -3
3 2 2
=<-4+6, -(4+9), 4+6>
=<2,-13,10>
The second vector is obtained by reversing the direction, namely <-2,13,-10>
Thus the two vectors are <2,-13,10> and <-2,13,-10>.