K2SO4 MgSO4 Al2(SO4)3 Ge2(SO4)4
KNO3 Mg(NO3)2 Al(NO3)3 Ge(NO3)4
KCH3COO Mg(CH3COO)2 Al(CH3COO)3 Ge(CH3COO)4
Note: all of the numerical are subscript to each element or compound.
Answer:
Using cobalt glass could be helpful to identify elements that weakly emit blue and/or violet.
Explanation:
There are 3 moles of are produced in neutralization when 1. 5 mole of reacts with
The neutralization reaction between magnesium hydroxide and sulfuric acid is given as,
→
from above chemical equation , we can conclude the molar ratio = 1:2
It means two moles of water molecule is produce from one mole of magnesium hydroxide.
So, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide = 1. 5 mole× 2 = 3 moles
Therefore, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide is 3 moles.
To learn more about neutralization
brainly.com/question/27891712
#SPJ4
Molar mass:
Ca(OH)₂ = 74.093 g/mol
Ca₃(PO₄)₂ = 310.17 g/mol
Mole ratio:
<span>2 Na</span>₃<span>PO</span>₄<span> + 3 Ca(OH)</span>₂<span> = Ca</span>₃<span>(PO</span>₄<span>)</span>₂<span> + 6 NaOH
</span>
3 x 74.093 g Ca(OH)₂ ----------- 310.17 g Ca₃(PO₄)₂
?? g Ca(OH)₂ ----------- 3.09 g Ca₃(PO₄)₂
Mass of Ca(OH)₂ = 3.09 x 3 x 74.093 / 310.17
Mas of Ca(OH)₂ = 686.84211 / 310.17
= 2.214 g of Ca(OH)₂
hope this helps!
Answer:
Glucose will be least soluble in non polar solvent
Explanation:
Glucose is a polar compound
According to VSEPR theory like compounds are soluble in like solvents means polar compounds are soluble in polar solvents and non polar compounds are soluble in non polar compounds
As glucose is a polar compound so it will be more soluble in polar solvent and least soluble in non polar solvent