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2 years ago

How many grams of calcium hydroxide must react to give 3.09 g of Ca3(PO4)2?

1 answer:

7 0

Molar mass:

Ca(OH)₂ = 74.093 g/mol
Ca₃(PO₄)₂ = 310.17 g/mol

Mole ratio:

2 Na₃PO₄ + 3 Ca(OH)₂ = Ca₃(PO₄)₂ + 6 NaOH

3 x 74.093 g Ca(OH)₂ ----------- 310.17 g Ca₃(PO₄)₂
?? g Ca(OH)₂ ----------- 3.09 g Ca₃(PO₄)₂

Mass of Ca(OH)₂ = 3.09 x 3 x 74.093 / 310.17

Mas of Ca(OH)₂ = 686.84211 / 310.17

= 2.214 g of Ca(OH)₂

hope this helps!

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TiliK225 [7]

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Round to the nearest whole number. The 1 in the tenth place tells us to leave the number as is.

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